Path: utzoo!utgpu!news-server.csri.toronto.edu!bonnie.concordia.ca!thunder.mcrcim.mcgill.edu!snorkelwacker.mit.edu!apple!julius.cs.uiuc.edu!usc!elroy.jpl.nasa.gov!turnkey!orchard.la.locus.com!fafnir.la.locus.com!dana From: dana@locus.com (Dana H. Myers) Newsgroups: sci.electronics Subject: Re: 80386. Message-ID: <1991Jan16.214955.2836795@locus.com> Date: 16 Jan 91 21:49:55 GMT References: <1990Dec28.210731.10685@zoo.toronto.edu> <3340012@hpcvca.CV.HP.COM> Organization: Locus Computing Corporation, Inglewood, CA Lines: 32 In article <3340012@hpcvca.CV.HP.COM> scott@hpcvca.CV.HP.COM (Scott Linn) writes: >/ hpcvca:sci.electronics / dana@locus.com (Dana H. Myers) / 12:51 pm Jan 14, 1991 / > >>Power is given by: >> >> P=IV >> >> Where: >> P = power in Watts >> I = current in Amperes >> V = voltage in Volts > >Right, and I = C * dv/dt, so P = C * V * dv/dt. > >In CMOS dv is equal to the supply (transitions are from supply to >ground), so P = C * V^2 / dt. But, 1/dt is the same as switching frequency, >so Pdynamic = C * V^2 * f, not > >> Pdynamic = V^2 * 2 * Pi * f * C, > >which gives you a value over 6 times larger than the actual power >dissipation. Right. As I was writing the original posting, I was asking myself, is this really correct? I looked it up, and, sure enough, the 2*Pi component is incorrect. Of course, this does not affect the discussion of the relationship of frequency and power consumption. -- * Dana H. Myers KK6JQ | Views expressed here are * * (213) 337-5136 | mine and do not necessarily * * dana@locus.com | reflect those of my employer *