Path: utzoo!attcan!uunet!bellcore!porthos!bae!snk
From: snk@bae.bae.bellcore.com (Samuel N Kamens)
Newsgroups: comp.unix.questions
Subject: getting a field from a line in awk/sed/?
Message-ID: <1991Jan9.162817.17038@porthos.cc.bellcore.com>
Date: 9 Jan 91 16:28:17 GMT
Sender: @porthos.cc.bellcore.com
Reply-To: snk@bae.bae.bellcore.com (Samuel N Kamens)
Organization: Bell Communications Research
Lines: 38



I'm sorry if anybody already got this -- I posted it
yesterday, and it doesn't seem to have made it off
the machine I posted it on.

The question I had was, how can I use UNIX tools to 
get one field out of a line?

The input will look like this:

Rank   Owner      Job  Files                                 Total Size
1st    fort       24   (standard input)                      40354 bytes
3rd    root       178  standard input                        57 bytes
4th    mike       25   (standard input)                      26895 bytes
6th    rdg        686  (standard input)                      733 bytes
7th    bdt        688  (standard input)                      31053 bytes



And the output should look like this:

Owner
fort 
root 
mike 
rdg  
bdt  


Any ideas?


-------------------------------------------------------------------------------
Sam Kamens					Bell Communications Research
snk@cellar.bae.bellcore.com			Phone: (908) 699-7381
444 Hoes Lane  Room RRC 1C-205
Piscataway, NJ 08854