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From: dsg@cci632.UUCP (David Greenberg)
Newsgroups: comp.sys.amiga
Subject: Re: Compairing C values
Message-ID: <49780@cci632.UUCP>
Date: 5 Feb 91 20:34:53 GMT
References: <rat.3380@hotcity.UUCP>
Reply-To: dsg@ccird1.UUCP (David Greenberg)
Organization: Computer Consoles Inc. an STC Company, Rochester, NY
Lines: 49

>	I have + as an input arguement via *argv[] and whenever I try to
>compare its value it comes out as a 0.  For instance...  If I compile a
>program like this:
>
>#include <stdio.h>
>#include <math.h>
>
>void main(int argc, char *argv[])
>
>{
>
>        And I type "test +" (I would name the file test) it would just print a
>equals 0.  Any help would be appereciated...
>char a = argv[1];
>if (a = '+') printf("a equals +");
>if (a = '0') printf("a equals '0'");
>if (a = 0) printf("a equals 0");
>}

	I think you want to use a double '=' here ie : (a='+' sets a equal
		to plus) a=='+' tests for equality)

if (a == '+') printf("a equals +\n");
if (a == '0') printf("a equals '0'\n");
if (a == 0) printf("a equals 0\n");  /* don't know what you are doing here?? */

(Also, use \n (newlines) to output the line. C uses buffered output and will not
print until a newline (\n) is encountered (or an fflush(stdout) is done).

	OR you could use a switch statement:



	switch (a) {

case '+':	printf("a equals +\n");
		break;
case '0':	printf("a equals '0'\n");
		break;
default:	printf("Neither + or '0'\n");

	}


	Hope this is what you need..

						Dave