Path: utzoo!utgpu!news-server.csri.toronto.edu!rutgers!maverick.ksu.ksu.edu!unmvax!ariel.unm.edu!triton.unm.edu!ee5391aa From: ee5391aa@triton.unm.edu (Duke McMullan n5gax) Newsgroups: sci.electronics Subject: Re: 12 to 9 volts dc Message-ID: <1991Feb11.012255.3022@ariel.unm.edu> Date: 11 Feb 91 01:22:55 GMT References: <1991Feb10.220719.17078@cbnewsl.att.com> Distribution: usa Organization: University of New Mexico, Albuquerque NM Lines: 87 In article <1991Feb10.220719.17078@cbnewsl.att.com> wally@cbnewsl.att.com (Brian S Walden) writes: >I want to take my old Sony Dicsman D-5 in the car with me, >the problem is that it requires 9 volts and 1/2 amp. OK: First, let's think 13.6 volts, not 12. That's the actual (as opposed to nominal) voltage when you're running the engine. Second, you _can_ use a resistor/zener_diode/buffer_transistor circuit such as the one you mention, but there are easier ways. We want to carve about 4.6 volts off that 13.6. If we call it 4.5, and you can come up with a 4.5 volt zener, then just put the zener in series with the load: + 12V o----------------|<-----------o + 9.1V 4.5V zener diode Negative is ground, of course. Note that the zener diode is installed "back- ward" to the way normal diodes are placed. It's used in "reverse conduction" mode. A problem is that that diode is dropping 4.5 volts at half an amp... that comes to 2.25 watts. As a safety fudge, you'd want a diode that could handle twice that...say, 5 watts. 5 watt zeners aren't cheap. Also, note that that drop assumes a significant current being drawn. As the current gets very small (<1mA, typically), the voltage will start to rise. This _usually_ isn't a problem, but for a CYA it can't hurt to put a small load...say, an LED with a current-limiting resistor (2.2 kilohms or so)...across the 9V side. This will stabilize the current, and give you a pilot lamp to boot. Stick a 3/4 amp or so fuse in the circuit, too. Slo-blo is recommended. Again, note the polarity of that diode. Also, be warned: If that zener should develop an internal short, the full 13.6 volts will be dumped into your load. If you install it backward, you will get just under 13 volts into your load. If you're lucky, the fuse will go before your DiskMan. _If_ you're lucky.... There's also a junk-box solution: 1 amp silicon rectifiers are widely avail- able, cheap, and many of us have a bunch lying around. The forward drop on a silicon diode is nominally 0.7V; actually 0.626 is a _very_ good average fig- gure. Lesee...0.626 into 4.6 is...7.3bleep, so if we use seven rectifiers in series, we lose about 4.4 volts leaving us with just under 9.2 volts. The circuit looks like this: +12V o------->|-->|-->|-->|-->|-->|-->|-------------o +9V seven silicon rectifiers, 1A at 50V or so. This time, note that the diodes all point downstream the way they're "sup- posed" to. If you need more current, it's easy to find 6A or even 10A rectifiers. Consider the rectifiers as all one component, then install the fuse and pilot light as before. Each diode dissapates about 0.626 times the current. Stay under 1 amp, and you should be safe. The PIV of the rectifiers isn't a worry, and 50V is about the lowest (and cheapest) type you'll find. You have some more safety here, too. Failure of more than one of the diodes (shorting-type failure, that is) is pretty unlikely in any situation that doesn't involve a blown fuse. Another advantage is that all the components pass the strongest test of availability that I know. Radio Schlock carries 'em.... Best o' luck, d PS -- A final caveat: It's unlikely to happen, but make sure you have _sili- con_ (not germanium) diodes, and make sure they're not Schottky or "hot car- rier" silicon diodes. All those diodes have a forward drop of about 0.3V, and if you're using a rectifier chain, you're like to do unpleasant things to your load. Germanium rectifiers are rare, and Schottky rectifiers are both rare and expensive. If you're worried about it, you can measure the forward drop very easily: Just put the diode in series with a small load (say, a flash- light lamp) powered with a battery, and measure the drop with a voltmeter. It should be between 0.6 and 0.7 volts. d -- "Got to slap these Goddamn Third World nations around, Flynn," he said, "until they learn some manners." -- Gregory MacDonald, from _Flynn_ Duke McMullan n5gax nss13429r phon505-255-4642 ee5391aa@triton.cirt.unm.edu