Path: utzoo!utgpu!news-server.csri.toronto.edu!cs.utexas.edu!swrinde!zaphod.mps.ohio-state.edu!wuarchive!psuvax1!rutgers!soleil!mlb.semi.harris.com!cica4.mlb.semi.harris.com!jws From: jws@cica4.mlb.semi.harris.com (James W. Swonger) Newsgroups: sci.electronics Subject: Re: Best way to power a hungry halogen bulb? Message-ID: <1991Feb13.134907.20122@mlb.semi.harris.com> Date: 13 Feb 91 13:49:07 GMT References: <1991Feb13.033718.11978@ecf.utoronto.ca> Sender: news@mlb.semi.harris.com Organization: Harris Semiconductor, Melbourne FL Lines: 10 Nntp-Posting-Host: cica4.mlb.semi.harris.com Try four AA NiCd batteries. Nominal voltage will be 4.8V; the package will end up about 1"x1"x2". AAs are usually about 450mAH; the "9V" cells are about 75maH as I recall. If you take apart the generic "9V" you will find 6 small cylindrical cells. Cutting the connection and using four removes the need for the dropping diode. You still end up with a lame battery. The newer 8.4V batteries use a stack of flat cells specially designed for the "9V" application rather than the cylinder sort which seem to be Q&D adaptations of the AA, cut off at the knees.