Path: utzoo!utgpu!news-server.csri.toronto.edu!cs.utexas.edu!uunet!microsoft!jimad
From: jimad@microsoft.UUCP (Jim ADCOCK)
Newsgroups: comp.lang.c++
Subject: Re: Simple example results
Message-ID: <70774@microsoft.UUCP>
Date: 19 Feb 91 17:37:34 GMT
References: <1991Feb14.165716.14417@cc.ic.ac.uk> <604@taumet.com>
Reply-To: jimad@microsoft.UUCP (Jim ADCOCK)
Organization: Microsoft Corp., Redmond WA
Lines: 29

In article <604@taumet.com> steve@taumet.com (Stephen Clamage) writes:
|rb@cc.ic.ac.uk (Robin Becker) writes:
|
|>Someone posted the following simple inheritance example recently
|>here are the results from TC++ and Zortech 2.1
|
|>class derived : public base
|>{
|>public: 
|>/*	virtual void whatami() { printf("I'm a derived.\n"); } */
|>	derived() { printf("In the derived constructor "); whatami(); }
|>	~derived() { printf("In the derived destructor "); whatami(); }
|>};
|
|Since whatami is commented-out in class derived, there is no way to
|print the phrase "I'm a derived".

Sorry for the confusion!  I intended to post a version where whatami()
above was not commented out [I commented out the above line while double-
checking my results]  With the line commented back in, my original statements
should hold.

|Within the constructor or destructor for any class, virtual function calls
|can refer only to functions in the current or base classes, never to 
|functions in any derived class.  (In a constructor, the derived class
|doesn't exist yet, so you can't refer to its members.  In a destructor,
|the derived class is gone, so you can't refer to its members.)

I agree.  The appropriate reference is ARM section 12.7 page 294.