Path: utzoo!utgpu!news-server.csri.toronto.edu!cs.utexas.edu!usc!zaphod.mps.ohio-state.edu!rpi!crdgw1!greenba From: greenba@gambia.crd.ge.com (ben a green) Newsgroups: sci.electronics Subject: Re: A question about the Nyquist theorm Message-ID: Date: 21 Feb 91 14:54:46 GMT References: <6607@healey> <883@idacrd.UUCP> <4402@eastapps.East.Sun.COM> Sender: news@crdgw1.crd.ge.com Followup-To: sci.electronics Distribution: na Organization: GE Corporate Research & Development Lines: 24 In-reply-to: gsteckel@vergil.East.Sun.COM's message of 20 Feb 91 23:56:43 GMT In article <4402@eastapps.East.Sun.COM> gsteckel@vergil.East.Sun.COM (Geoff Steckel - Sun BOS Hardware CONTRACTOR) writes: In article <883@idacrd.UUCP> mac@idacrd.UUCP (Robert McGwier) writes: From article <6607@healey>, by grayt@Software.Mitel.COM (Tom Gray): > The shape of the wave is preserved within the sampling pulse. This > information allows representation of a signal at exactly 1/2 > the Nyquist freqency. I pose the following question. Suppose you are sampling at rate N samples per second, and you see a constant value V for your A/D sample. Is the frequency of the signal which produced those samples 0 or N/2? Since AARRGGGHHH! The Nyquist criterion requires that sampling be GREATER THAN the highest frequency of interest. Note also that the amplitude response near Fs/2 rolls off towards 0 (sin X / X response). Furthermore, the claim that "the shape of the wave is preserved within the smpling pulse" would imply that an analytic signal could be reproduced entirely from ONE sample, since all the derivatives of the signal are available in the sample. Can't believe Nyquist said that. -- Ben A. Green, Jr. greenba@crd.ge.com Speaking only for myself, of course. Brought to you by Super Global Mega Corp .com