Path: utzoo!utgpu!news-server.csri.toronto.edu!cs.utexas.edu!uunet!world!wmm
From: wmm@world.std.com (William M Miller)
Newsgroups: comp.lang.c++
Subject: Re: Overloaded Function Ambiguity Resolution Problems
Message-ID: <1991Feb27.204841.14690@world.std.com>
Date: 27 Feb 91 20:48:41 GMT
References: <1991Feb27.084909.5063@newcastle.ac.uk>
Organization: The World Public Access UNIX, Brookline, MA
Lines: 34

Graham.Parrington@newcastle.ac.uk (Graham D. Parrington) writes:
> class Base
> {
> public:
>     Base(char *) { cout << "Base::Base(char *)\n"; }
>     void func(char*) { cout << "Base::func(char *)\n"; }
> };
>
> class Derived:public Base
> {
> public:
>     void func(const Base&){ cout << "Derived::func(const Base&)\n"; }
>
> };
>
> main()
> {
>     Derived *d = new Derived();
>
>     d->func("hello");
> }
>
> What should it output?

The cfront output is correct, G++ is wrong.  See E&S section 13.1, page 310:
"Two function declarations of the same name refer to the same function if
they are in the same scope and have identical argument types (section 13).
A function member of a derived class is NOT in the same scope as a function
member of the same name in a base class."  In this example, d->func("hello")
can only refer to Derived::func(const Base&), since Base::func(char*) is
hidden in the scope of Derived.

-- William M. Miller, Glockenspiel, Ltd.
   wmm@world.std.com