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From: gary@hpavla.avo.hp.com (Gary Jackoway)
Newsgroups: comp.lang.c
Subject: Re: Macros in ANSI C
Message-ID: <9130022@hpavla.avo.hp.com>
Date: 4 Mar 91 18:54:10 GMT
References: <1172@intelisc.isc.intel.com>
Organization: Hewlett-Packard Avondale Division
Lines: 30

Mojy Mirashrafi writes:

> Here is my question:

> In the old C if you wanted to define a macro to convert its parameter to a 
> char you would write a macro like this:

> #define conv(s) 's'

> and if you used "conv(X)" in your code you would get 'X'.

> In ANSI C the "'" prevents evaluation of the enclosed characters.
> The above macro will expand to: 's'. Is there a way to escape the "'"s, 
> in ANSI C?

I don't want to get into an argument about whether it should have worked like
you say it did in the past, so I'll just give you a (mildly ugly) solution.

Since we now have the "stringize" # operator, all you have to do is this:

#define CHARIZE(c) (#c)[0]

That'll do it.

> Thanx.

Your welcome, but don't tell anyone I came up with this solution.
				    -

Gary Jackoway