Path: utzoo!utgpu!watserv1!ria!obelix!ptoper From: ptoper@obelix (Andy Nagy) Newsgroups: comp.sys.amiga.hardware Subject: Re: Watts of the A3000, A1950, JX300, etc Message-ID: <2468@ria.ccs.uwo.ca> Date: 13 Mar 91 00:50:59 GMT References: Sender: news@ria.ccs.uwo.ca Reply-To: ptoper@obelix (Andy Nagy) Lines: 51 In article , andrewsr@u2.rutgers.edu (Rich Andrews) writes: > > Hello All! > > I am considering purchasing a TrippLite Line Conditioner Stabilizer > and Brown Out Protector (whew, now there's a mouthfull!) > > Q: How many watts do the following pieces of hardware require? > 1. Amiga 3000 (w/ 18MB of on board memory) > (And a 200MB SCSI 2ond drive) > 2. A1950 monitor > 3. JX300 scanner > > > Q2: For the layman, what is the relationship between watts and amps? > > Thanks in advance, > -Rich > -- > // Rich | "If there is nothing wrong with me, then maybe there is > \X/ Andrews | something wrong with the universe." - Beverly The simplest answer to your first answer is to lookup the maximum power ratings in your manuals and add them up. This will give you the max amount of power your system could safely handle, not necessarily the actual amount you are using. Answering your second question is easier: power = voltage * current where power is measured in watts (W), voltage in volts (V) and current in amperes (A), both voltage and current are expressed in RMS units (Root Mean Square). For example a 100 W light bulb in a 120 V circuit will have a current draw of current = power / voltage = 100 W / 120 V = 833 mA Because the power line is usually considered constant, the relation- ship between power and current is linear. This means that if one increases the other increases, the inverse is also true. Hope this helps. ------------------------------------------------------------------------------- Andy Nagy (ptoper@asterix.gaul.csd.uwo.ca) The University of Western Ontario, London, Canada "Dee do do do, dee da da da, thats all I want to say to you" -- The Police