Path: utzoo!attcan!telly!lethe!tvcent!comspec!humvax!becker!hybrid!scifi!bywater!uunet!bria!mike
Newsgroups: comp.unix.questions
Subject: Re: Changing .zoo archive to .lzh archive: help!
Message-ID: <456@bria>
Date: 17 Feb 91 04:54:20 GMT
References: <885@caslon.cs.arizona.edu>
Reply-To: uunet!bria!mike
Distribution: usa
Organization: MGI Group International, Los Angeles, CA
Lines: 52
Followup-To:
Keywords:

In an article, cs.arizona.edu!dave (Dave P. Schaumann) writes:
>
>I am trying to write a script that will allow me to convert zoo archives
>to lharc archives under Unix.  Here's what I have so far:
>
>mkdir xxx
>cd xxx
>zoo xq// ../$1.zoo
>lharc aq ../$1.lzh * `no-dot .*`
>cd ..
>rm -r xxx
>
>Where "no-dot" is a simple program that echos back everything in argv[] that
>isn't "." or ".."

Actually, you can use ``find'' for this purpose ...

	lharc aq ../$lzh `find . \( ! -name "." -a ! -name ".." \) -print`

So, how about this snippet ...?

--- snip --- snip --- snip --- snip --- snip --- snip --- snip --- snip ---

dir=.dir$$
mkdir $dir || exit
for archive in $*; do
   cd $dir
   zoo xq// ../${archive}.zoo
   lharc aq ../${archive}.lzh `find . \( ! -name "." -a ! -name ".." \) -print`
   cd ..
   rm -fr $dir
   mkdir $dir || exit
done
rm -fr $dir

--- snip --- snip --- snip --- snip --- snip --- snip --- snip --- snip ---

>Now, I could write a program to generate a temporary directory name using
>getpid() and some unlikely template, like "xx-######-temp".  What I need to
>know is:
>
>  1.  Is it a reasonable assumption that no two concurrent getpid()'s will
>      return the same value?

It is _very_ reasonable to assume this.  Updates to the kernel proc table 
are atomic, insuring that no two "concurrent" processes have the same PID.

Hope this helps.
Cheers,
-- 
Michael Stefanik, MGI Inc., Los Angeles| Opinions stated are not even my own.
Title of the week: Systems Engineer    | UUCP: ...!uunet!bria!mike
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