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From: art@pilikia.pegasus.com (Art Neilson)
Newsgroups: comp.unix.questions,comp.unix.shell
Subject: Re: Awk with passed parameters
Summary: Use shell quoting
Keywords: awk bsd shell
Message-ID: <1991Mar10.033553.28978@pilikia.pegasus.com>
Date: 10 Mar 91 03:35:53 GMT
References: <3022@dsacg3.dsac.dla.mil>
Organization: Pilikia, Honolulu
Lines: 27

In article <3022@dsacg3.dsac.dla.mil> nfs1675@dsacg3.dsac.dla.mil ( Michael S Figg) writes:
>
>
>I'm trying to write a short shell script using awk to list files in the
>current directory that have todays' date on them. It seems like something
>like this should work, but I haven't had any luck:
>
>set d = `date`
>ls -l | awk '$5 == x && $6 == y  {print}' x=$d[2] y=$d[3]

Here's my solution using the Bourne shell and standard awk.

:

date="`date`"
set $date

ls -l | awk '
BEGIN {
	mm = '\"$2\"'
	dd = '\"$3\"' + 0
}
	$6 == mm && $7 == dd { print }
'
-- 
Arthur W. Neilson III		| INET: art@pilikia.pegasus.com
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