Path: utzoo!news-server.csri.toronto.edu!rutgers!cbmvax!bagate!dsinc!unix.cis.pitt.edu!zaphod.mps.ohio-state.edu!uakari.primate.wisc.edu!caen!uwm.edu!bionet!agate!dog.ee.lbl.gov!pasteur!cory.Berkeley.EDU!navas From: navas@cory.Berkeley.EDU (David C. Navas) Newsgroups: comp.sys.amiga.hardware Subject: Re: Watts of the A3000, A1950, JX300, etc Message-ID: <12003@pasteur.Berkeley.EDU> Date: 15 Mar 91 04:19:25 GMT References: Sender: news@pasteur.Berkeley.EDU Reply-To: navas@cory.Berkeley.EDU Lines: 36 In article andrewsr@u2.rutgers.edu (Rich Andrews) writes: > >Hello All! Hi there. >Q2: For the layman, what is the relationship between watts and amps? Q1 I have no idea about. This one I'll attempt a layman's answer to (if my freezing fingers hold out). Imagine standing under a waterfall [a small one, as you couldn't "stand" under a large one :)]. Now, a certain volume of water is flowing around you over a certain period of time. That is a rough analogy to amperage. Specifically [correct if wrong, please], amperage is the flow of charge per unit time. Also, this same water is hitting you with a certain force. Make the waterfall "taller", and the water will start to hurt you (because it's falling faster) when it hits you. The volume of water hasn't changed, just the force that it has when it impacts. That's wattage. In the same way, force more water to flow over the waterfall (increase the amperage), and the waterfall wil also hurt more, and may eventually reduce ones posture :). Again, this is analogous to an increase of wattage. Voltage is, as you might suspect, the "height" of the waterfall. >Thanks in advance, Hope it helps... David Navas navas@cory.berkeley.edu "Oh, that's an Apple??? I though they just shot themselves in the head..." [Also try c186br@holden, c260-ay@ara and c184-ap@torus]