Xref: utzoo comp.unix.questions:29486 comp.unix.shell:1690
Path: utzoo!news-server.csri.toronto.edu!cs.utexas.edu!wuarchive!uwm.edu!bionet!agate!ucbvax!unisoft!fai!sequent!lugnut
From: lugnut@sequent.UUCP (Don Bolton)
Newsgroups: comp.unix.questions,comp.unix.shell
Subject: Re: Awk with passed parameters
Keywords: awk bsd shell
Message-ID: <55345@sequent.UUCP>
Date: 14 Mar 91 22:18:14 GMT
References: <3022@dsacg3.dsac.dla.mil> <1991Mar10.033553.28978@pilikia.pegasus.com>
Reply-To: lugnut@sequent.UUCP (Don Bolton)
Organization: Sequent Computer Systems, Inc
Lines: 39

In article <1991Mar10.033553.28978@pilikia.pegasus.com> art@pilikia.pegasus.com (Art Neilson) writes:
>In article <3022@dsacg3.dsac.dla.mil> nfs1675@dsacg3.dsac.dla.mil ( Michael S Figg) writes:
>>
>>
>>I'm trying to write a short shell script using awk to list files in the
>>current directory that have todays' date on them. It seems like something
>>like this should work, but I haven't had any luck:
>>
>>set d = `date`
>>ls -l | awk '$5 == x && $6 == y  {print}' x=$d[2] y=$d[3]
>
>Here's my solution using the Bourne shell and standard awk.
>
>:
>
>date="`date`"
>set $date
>
>ls -l | awk '
>BEGIN {
>	mm = '\"$2\"'
>	dd = '\"$3\"' + 0
>}
>	$6 == mm && $7 == dd { print }
>'

I may be missing something obvious here but why use awk at all?

IFS=': '
set `date`
hrs=$4
m=$2   

etc

works just fine for a 12 hour clock display I use from the date output


Don "1600 hrs reminds me of people with bad haircuts and boots" Bolton