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From: jik@athena.mit.edu (Jonathan I. Kamens)
Newsgroups: comp.unix.questions,comp.unix.shell
Subject: Re: Awk with passed parameters
Keywords: awk bsd shell
Message-ID: <1991Mar15.182242.18780@athena.mit.edu>
Date: 15 Mar 91 18:22:42 GMT
References: <3022@dsacg3.dsac.dla.mil> <1991Mar10.033553.28978@pilikia.pegasus.com> <55345@sequent.UUCP>
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Organization: Massachusetts Institute of Technology
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In article <55345@sequent.UUCP>, lugnut@sequent.UUCP (Don Bolton) writes:
|> I may be missing something obvious here but why use awk at all?
|> 
|> IFS=': '
|> set `date`
|> hrs=$4
|> m=$2   
|> 
|> etc
|> 
|> works just fine for a 12 hour clock display I use from the date output

  How does this solve the problem that the original poster is trying to solve?

  He wanted to use awk to filter the output of "ls" to print out only those
files that were modified today.  What you posted above explains how to set the
month and day to shell variables.  But how are you going to then use that to
filter the output of ls?  If you try to do it completely in the shell, you're
going to have to pipe the output of ls into a loop or function that matches
each line against the month and day.  The matching will have to be done using
"test" or "expr".  Which means (unless you've got a shell with "test" built
in) that you're going to be forking a process to do the test for every line in
the ls listing.

  Is that really what you intended to suggest, or am I missing something?

-- 
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