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From: c60b-1eq@web-1b.berkeley.edu (Noam Mendelson)
Newsgroups: comp.lang.c
Subject: Re: Simple atof() question
Message-ID: <1991Mar19.192212.14868@agate.berkeley.edu>
Date: 19 Mar 91 19:22:12 GMT
References: <1214@caslon.cs.arizona.edu>
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In article <1214@caslon.cs.arizona.edu> armstron@cs.arizona.edu (Jim Armstrong) writes:
>
>How can I get atof() to return a float instead of a double? 
>When I run this simple program I get n = 37.549999 instead of
>n = 37.55.  What am I doing wrong?
>
>
>#include <stdio.h>
>
>main()
>{
>
>double atof();
>char buf[10];
>float n;
>
>strcpy(buf,"37.55");
>n = (float) atof(buf);
>printf("n = %f\n",n);
>
>}

atof() _is_ returning a float.  It is a different matter if you would
like to round it off to two decimal places.  In that case you might
want to try floor(x*100)/100.

===============================================================
Noam Mendelson                       | "I haven't lost my mind,
c60b-1eq@web.Berkeley.EDU            |  it's backed up on tape
University of California at Berkeley |  somewhere."