Path: utzoo!utgpu!news-server.csri.toronto.edu!cs.utexas.edu!usc!samsung!uunet!igor!rutabaga!jls
From: jls@rutabaga.Rational.COM (Jim Showalter)
Newsgroups: comp.object
Subject: Re: Documenting OO Systems
Keywords: operators
Message-ID: <jls.670218725@rutabaga>
Date: 29 Mar 91 03:52:05 GMT
References: <jls.669768656@rutabaga> <299@orbit.gtephx.UUCP> <1991Mar25.145441.1@happy.colorado.edu> <20106@alice.att.com> <3481@engadm3.csd.mot.com> <DWWX.91Mar25215016@cbnewsk.ATT.COM> <jls.669956827@rutabaga> <1991Mar26.191259.14470@i88.isc.com> <4693@osc.COM>
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>One thing i like about C is that when you type something you know what it's
>going to do.

Okay, what is this going to do?:

    int j (int y, int m, int d) {
    int m_d[12] = {31,28,31,30,31,30,31,31,30,31,30,31};
    if (m<1 || m>12) return 0;
    int l = !(y%4) && y&400;
    if (d<1 || d>(m_d[m-1] + (m==2 && y))) return 0;
    int dd = 0;
    for (int i=0; i<m-1; i++) dd += m_d[i];
    return dd + d + (m>2 && y);
    }

You should be able to tell me right off the bat--you think English sucks
as a programming language, and this is DEFINITELY not written in English.
--
***** DISCLAIMER: The opinions expressed herein are my own, except in
      the realm of software engineering, in which case I've borrowed
      them from incredibly smart people.