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From: grover@cleanhead.cs.unlv.edu (Kevin Grover)
Newsgroups: comp.sys.handhelds
Subject: Re: A Bug or not ?
Message-ID: <1991Apr11.202106.987@unlv.edu>
Date: 11 Apr 91 20:21:06 GMT
References: <00946F29.17B42000@MAPLE.CIRCA.UFL.EDU>
Sender: news@unlv.edu (News User)
Reply-To: grover@cleanhead.cs.unlv.edu (Kevin Grover)
Organization: UNLV Computer Science and Electrical Engineering
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In article <00946F29.17B42000@MAPLE.CIRCA.UFL.EDU>, bobdobbs@oak.circa.ufl.edu (Amiga Dude) writes:
) Well I haven't had my HP48SX long now, but I was messing around with the units,
) and did this simple operation:
) 
)            45_F (45 Degrees F)
)            45_F (     "      )
)  Well I put them on the stack, levels 2: and 1: then pushed the nifty + (plus)
) key, and I expected to see 90_F, but instead I saw 549.67_F, well needless to
) say, I looked in the manual, and it said something about Convert performs an
) absolute temp. scale conversion, including the additive constants.  Well I did
) not Convert, I merely added the 2.  I suppose I am forgetting something from my
) old basic Science days, so what gives ??? Anyone know a simple soln' to the
) problem (not that it is of earth-shaking importance, but just curious) ?
) 
) Thanks,
) Scott D. Alden

I think that the calculator is converting the F to Kelvin and then doing the
addition.  However, there is more to it than just this, because just converting
to Kelvin and adding gave me 560.7  using   (5/9(F - 32) + 273.15) to get Kelvin
from Fahr.  (NOTE:  this is an assumption on my part.  I made it because the 
eq lib does similar things (beacuse most formulas require abs temp in Kelvins
- look up UBASE for more info)  I am passing it along as a possible lead to the
true answer.  (Anyway, hope it helps.)

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