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From: jhz@cunixa.cc.columbia.edu (Jennifer H. Zemsky)
Subject: Re: Need help with quoting and the CPP
Message-ID: <1991Apr22.014237.16836@cunixf.cc.columbia.edu>
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Reply-To: jhz@cunixa.cc.columbia.edu (Jennifer H. Zemsky)
Organization: Columbia University
References: <230@wimpy.nms.gdc.portal.com>
Date: Mon, 22 Apr 1991 01:42:37 GMT

In article <230@wimpy.nms.gdc.portal.com> bergquis@nms.gdc.portal.com (Brett Bergquist) writes:
>Is there any way to expand an argument to a macro and at the same time
>surround it with quotes (making is a quoted string).  For example if
>STRING is defined as:
>
>#define STRING test string
>
>Is there any way to define a macro "QUOTE" so that:
>
>char* s = QUOTE(STRING);
>
>while produce:
>
>char *s = "test string";
>
from k&r (2nd ed), 4.11.2:
if ... a parameter is preceded by a # in the replacement text, the combination
will be expanded into a quoted string with the parameter replace by the actual
argument. This can be combined with string concatenation to make, for
example, a debugging print macro:

#define dprint(expr) printf(#expr " = %g\n",expr)
When this is invoked, as in

dprint (x/y);

the macro is expanded into
printf("x/y" " = %g\n", x/y);
and the strings are concatenated ...
printf("x/y = %g\n",x/y);

(end quote)
you could try
#define QUOTE(x) #x

and see if it works.
(note: the extra information was to head off some other questions.)

>Thanks in advance.

no prob.

--hymie
jhz@cunixa.cc.columbia.edu
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