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From: persol@solan.unit.no (Per Solberg)
Newsgroups: comp.sys.handhelds
Subject: Re: HP48 w/o batteries
Keywords: HP48
Message-ID: <1991Apr19.143303.21502@ugle.unit.no>
Date: 19 Apr 91 14:33:03 GMT
References: <1991Apr18.052937.7060@ux1.cso.uiuc.edu>
Sender: news@ugle.unit.no
Reply-To: persol@solan.unit.no (Per Solberg)
Organization: Norwegian Institue of Technology
Lines: 30

In article <1991Apr18.052937.7060@ux1.cso.uiuc.edu>, creiman@ncsa.uiuc.edu (Charlie Reiman) writes:
|> Does anyone know how long the HP48's memory remains intact with the batteries
|> out?
|> 
|> ... you had to pull the batteries out of the calculator once to clear the
|> memory. As we all know, this doesn't do diddly to an HP, unless you leave them 
|> out for XX time.
|> 
|> I suddenly began to wonder, just what is XX for the 48?
|> 
|> Charlie Reiman					 creiman@ncsa.uiuc.edu

Before shipping my 48SX-A off to HP for upgrading to rev. E last week, I tried to
find out how long I could leave the batteries out without losing memory.
I started my removing the batteries, leaving them out for 5 minutes and then
reinserting them. As expected, memory was intact, so I tried again, this time for
10 minutes. Then I tried for 15, 20, 25 and 30 minutes and still no loss of
memory. As I had grown tired of trying, I decided not to investigate the matter
further.


Answer :  XX > 30 minutes.

I have only tested this on my own 48SX with no RAM/ROM-cards, and I don't know if
adding RAM/ROM-cards will have any effect.



Per Solberg
persol@solan.unit.no