Newsgroups: comp.sys.handhelds Path: utzoo!utgpu!news-server.csri.toronto.edu!rpi!zaphod.mps.ohio-state.edu!wuarchive!mit-eddie!bloom-beacon!bloom-picayune.mit.edu!athena.mit.edu!gimbel From: gimbel@athena.mit.edu (William A Gimbel) Subject: RE: HP48 w/o batteries Message-ID: <1991Apr21.182925.26038@athena.mit.edu> Sender: news@athena.mit.edu (News system) Organization: Massachusetts Institute of Technology References: <9104201150.AA08143@techst02.technion.ac.il> Date: Sun, 21 Apr 91 18:29:25 GMT Lines: 13 In article <9104201150.AA08143@techst02.technion.ac.il>, s2499576%techst02.technion.ac.il@TAUNIVM.TAU.AC.IL (Yaniv Shaya) writes: |> As much as I can remember, in the manual it is stated that the computer memory |> will last for (at least) 60 seconds - not very much, but then maybe I am wrong. The company, in this case HP, will always put a conservative estimate of the amount of time you have to replace the batteries in your calculator. I reality it could be anywhere from zero seconds to a whole day or more. Of course I am exaggerating, but I hope the point is clear. You will never know the exact time for your calculator unless you experiment, and are willing to wipe out memory at least once. (You could probably get a more realistic estimate also from HP if you are concerned with the actual amount of time.) -- Bill