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From: steven@pacific.csl.uiuc.edu (Steven Parkes)
Newsgroups: comp.lang.c++
Subject: implicit conversion to a reference
Message-ID: <1991May1.143350.19206@roundup.crhc.uiuc.edu>
Date: 1 May 91 14:33:50 GMT
Sender: news@roundup.crhc.uiuc.edu
Reply-To: steven@pacific.csl.uiuc.edu
Followup-To: comp.lang.c++
Organization: Coordinated Science Laboratory, University of Illinois
Lines: 31

Under cfront 2.0, in the following program, x does not seem to convert to
an (int&) the way that we think it should.  Any comments on what the correct
semantics for this syntax are? Could someone run it under cfront 2.1 and tell
us whether it produces an error or not ...

class Int {

  public:
    Int () {}
    Int ( int x ) : me ( x ) {}
    operator int& () { return me; }
    int* operator & () { return &me; }

  private:
    int me;
};

int f(int x ) { return x; }

main()
{
    Int x;

    x=10;		// works

    x+=5;		// works
    x = * &x;		// works

    f(x);		// this doesn't work ...
    f( (int&) x);	// ... but this does
}