Path: utzoo!utgpu!news-server.csri.toronto.edu!rpi!usc!elroy.jpl.nasa.gov!sdd.hp.com!wuarchive!uunet!auspex!guy From: guy@auspex.auspex.com (Guy Harris) Newsgroups: comp.os.mach Subject: Re: How many machines running Mach? Message-ID: <7689@auspex.auspex.com> Date: 8 May 91 17:15:57 GMT References: <7644@auspex.auspex.com> <1991May7.163912.615@bwdls61.bnr.ca> Distribution: comp Organization: Auspex Systems, Santa Clara Lines: 16 >I in fact asked, "Does this mean, you need not have Mach to be >certified as an OSF/1 compliant OS?", and the response I got back was >"Yes, you don't need Mach to be OSF compliant". Well, to be fair, as I understand it, the term "OSF/1" may refer both to a specification and to an implementation; no, you don't need Mach to be compliant with the specification, but the implementation of that specification that you get from OSF is based on Mach, and may be the easiest way to get a system compliant with the specification. (It's sort of like the SVID and System V; you don't *need* AT&T's code to be SVID-compliant, but the easiest way to be SVID-compliant may be to use it.) So, while an OSF/1-compliant system may not be based on Mach, an OSF/1 system - in the sense of a system built from OSF's code - is based on, among other things, Mach.