Path: utzoo!utgpu!news-server.csri.toronto.edu!rpi!zaphod.mps.ohio-state.edu!pacific.mps.ohio-state.edu!linac!att!news.cs.indiana.edu!ariel.unm.edu!cie!kgowen
From: kgowen@cie.uoregon.edu (Kevin Gowen)
Newsgroups: comp.os.msdos.programmer
Subject: Displaying ascii 10 and 12
Message-ID: <1991May16.014520.16721@ariel.unm.edu>
Date: 16 May 91 01:45:20 GMT
Reply-To: kgowen@cie.uoregon.edu (Kevin Gowen)
Organization: University of Oregon Campus Information Exchange
Lines: 20

OK, here is what should be a simple problem, but it has me stumped:

I'm trying to display an ascii chart on the screen:

         for (i=0; i<=255; i++)
	   {
             printf("%3d %3x %c", i, i, char(i));
             printf("\n");
           }

This works fine for *most* characters.  However, decimal 10 is the newline
character so when i=10 I am trying to print "\n" and all it does is, of
course, is put the cursor on a new line.  I don't get the ascii representation
of 10, which is a rectangular box with a circle inside.  How do I tell the
computer that I want to *see* the newline char, not the results of a newline?
There must be something real obvious that I'm missing.  You can post replies
here, as I read this group, or email is fine, too.  Thanks in advance.

-kevin
kgowen@cie.uoregon.edu