Xref: utzoo comp.theory.dynamic-sys:255 sci.math:17424 Path: utzoo!utgpu!news-server.csri.toronto.edu!rpi!zaphod.mps.ohio-state.edu!wuarchive!udel!princeton!phoenix!jwunsch From: jwunsch@phoenix.Princeton.EDU (Jared Wunsch) Newsgroups: comp.theory.dynamic-sys,sci.math Subject: Re: HELP: diagonalizability of nonhermitian matrices theorem Message-ID: <9575@idunno.Princeton.EDU> Date: 15 May 91 16:18:42 GMT References: <1991May13.135859.2737@lgc.com> <91133.162124BJK111@psuvm.psu.edu> <1991May14.102145.5659@bnlux1.bnl.gov> Sender: news@idunno.Princeton.EDU Followup-To: comp.theory.dynamic-sys Organization: Princeton University Lines: 13 In article <1991May14.102145.5659@bnlux1.bnl.gov> kyee@bnlux1.bnl.gov (kenton yee) writes: >hi, >we know any hermitian matrix H and any antihermitian matrix >A is diagonalizable. i want to prove that any linear combination >M = aH + bA are diagonalizable (a,b real). Can this be true? It seems to me that given an arbitrary matrix A, if we let A* be its Hermitian transpose, then we have A = (A+A*)/2 + (A-A*)/2 ie. A is a linear combination of a Hermitian and an anti-Hermitian matrix. So if the conjecture were true, we'd have every matrix diagonalizable.