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From: asqe-x-w-ic03@worms-emh1.army.mil (Udo Walter, SYS ADM, CDOIM)
Newsgroups: comp.unix.questions
Subject: Re: Half of a ls -l ? [INFO-UNIX Digest   V12#102]
Message-ID: <26906@adm.brl.mil>
Date: 15 May 91 14:00:18 GMT
Sender: news@adm.brl.mil
Lines: 15

robby@nuchat.sccsi.com (Robert Oliver Jr.) writes:

>   Has anybody out there ever printed out the size, date and name of a file
>without the permissions and owners just the size, date & name. I would like
>to know how you did it!

Try this one. It gives tells you also whether it's a file or a directory.
Put it in a scriptfile and make it executable.

ls -al $1 | nawk '{if (match($1,"d")) 
                    printf("<DIR> %7d %3s %2s %5s %s\n",$5,$6,$7,$8,$9)
                   else
                    printf("      %7d %3s %2s %5s %s\n",$5,$6,$7,$8,$9)}'| more

Udo Walter