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From: rouben@math16.math.umbc.edu (Rouben Rostamian)
Newsgroups: comp.unix.shell
Subject: Re: sed question
Message-ID: <1991May16.043510.16184@umbc3.umbc.edu>
Date: 16 May 91 04:35:10 GMT
References: <3880@wb3ffv.ampr.org>
Sender: newspost@umbc3.umbc.edu (News  posting account)
Organization: University of Maryland Baltimore County, Mathmatics Department
Lines: 30

In article <3880@wb3ffv.ampr.org> wmark@wb3ffv.ampr.org (Mark Winsor) writes:
>I know that 
>
>sed -n '/PATTERN1/,/PATTERN2/p' filename
>
>will print everything between pattern 1 & 2, but what if I only want the
>first occurence of these patterns in the file? I know I can pipe the above
>statement to sed '/PATTERN2/q' but there has got to be a way to do this
>in one sed process. Thanks.

Here it is -- one sed process:

sed -n -e '
/PATTERN1/,/PATTERN2/{
p
:loop
n
/PATTERN2/!{
p
bloop
}
p
q
}' <filename

--
Rouben Rostamian                          Telephone: (301) 455-2458
Department of Mathematics and Statistics  e-mail:
University of Maryland Baltimore County   bitnet: rostamian@umbc.bitnet
Baltimore, MD 21228,  U.S.A.              internet: rouben@math9.math.umbc.edu