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From: peterc@suite.sw.oz.au.sw.oz.au (Peter Chubb,-x27,6982322,3982735)
Newsgroups: comp.unix.shell
Subject: Re: sed question
Message-ID: <1991May17.043040.21660@softway.sw.oz.au>
Date: 17 May 91 04:30:40 GMT
References: <1991May16.043510.16184@umbc3.umbc.edu>
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Originator: peterc@suite.sw.oz.au

From article <1991May16.043510.16184@umbc3.umbc.edu>, by rouben@math16.math.umbc.edu (Rouben Rostamian):
> In article <3880@wb3ffv.ampr.org> wmark@wb3ffv.ampr.org (Mark Winsor) writes:
>>I know that 
>>
>>sed -n '/PATTERN1/,/PATTERN2/p' filename
>>
>>will print everything between pattern 1 & 2, but what if I only want the
>>first occurence of these patterns in the file? I know I can pipe the above
>>statement to sed '/PATTERN2/q' but there has got to be a way to do this
>>in one sed process. Thanks.
> 
> Here it is -- one sed process:
	(sed script using branches elided)

Why not use multiple -e options?  That's a little simpler than using
branches and labels. 

Thus:
	sed -n -e '/PATTERN1/,/PATTERN2/p' -e '/PATTERN2/,$d' filename


			Regards,

				- Peter Chubb

Softway Pty Ltd, P.O. Box 305, Strawberry Hills, NSW 2012, AUSTRALIA
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