Path: utzoo!utgpu!news-server.csri.toronto.edu!bonnie.concordia.ca!uunet!tellab5!vpnet!dattier
From: dattier@vpnet.chi.il.us (David W. Tamkin)
Newsgroups: comp.unix.shell
Subject: Re: sed question
Message-ID: <1991May17.002433.15615@vpnet.chi.il.us>
Date: 17 May 91 00:24:33 GMT
References: <3880@wb3ffv.ampr.org> <1991May16.043510.16184@umbc3.umbc.edu>
Organization: VPnet Public Access Unix, Villa Park, Illinois  60181-2206
Lines: 33

rouben@math16.math.umbc.edu (Rouben Rostamian) wrote in
<1991May16.043510.16184@umbc3.umbc.edu>:

| In article <3880@wb3ffv.ampr.org> wmark@wb3ffv.ampr.org (Mark Winsor) writes:
| >I know that 
| >
| >sed -n '/PATTERN1/,/PATTERN2/p' filename
| >
| >will print everything between pattern 1 & 2, but what if I only want the
| >first occurence of these patterns in the file? I know I can pipe the above
| >statement to sed '/PATTERN2/q' but there has got to be a way to do this
| >in one sed process. Thanks.

| Here it is -- one sed process:
| 
| sed -n -e '
| /PATTERN1/,/PATTERN2/{
| p
| :loop
| n
| /PATTERN2/!{
| p
| bloop
| }
| p
| q
| }' <filename

sed -n '/PATTERN1/,/PATTERN2/p
/PATTERN2/q' filename

David Tamkin  PO Box 7002  Des Plaines IL  60018-7002  dattier@vpnet.chi.il.us
GEnie:D.W.TAMKIN  CIS:73720,1570  MCIMail:426-1818  708 518 6769  312 693 0591