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From: gwyn@smoke.brl.mil (Doug Gwyn)
Newsgroups: comp.lang.c
Subject: Re: Using sizeof() on a parameter array
Message-ID: <16195@smoke.brl.mil>
Date: 20 May 91 04:13:22 GMT
References: <12151@jarthur.Claremont.EDU>
Organization: U.S. Army Ballistic Research Laboratory, APG, MD.
Lines: 12

In article <12151@jarthur.Claremont.EDU> jseidman@jarthur.Claremont.EDU (Jim Seidman) writes:
-void test(char param[80]) {
-    char local[80];
-    printf("sizeof(param) = %d\n", sizeof(param));
-    printf("sizeof(local) = %d\n", sizeof(local));
-}
-Now, I thought that this should print out the same size for both, namely
-80.  But according to MSC, local has a size of 80, and param has a size
-of 2 (the size of a pointer).

MSC is right.  The parameter DOES have type pointer-to-char; you've
just written in in an opaque way.