Path: utzoo!utgpu!news-server.csri.toronto.edu!rpi!usc!jarthur!uunet!tellab5!vpnet!dattier
From: dattier@vpnet.chi.il.us (David W. Tamkin)
Newsgroups: comp.unix.shell
Subject: Re: How to sort on right most column
Message-ID: <1991May23.233443.17752@vpnet.chi.il.us>
Date: 23 May 91 23:34:43 GMT
References: <felps.674313068@convex.convex.com> <1991May15.140902.23225@convex.com> <1991May22.191522.19709@jpradley.jpr.com>
Organization: VPnet Public Access Unix, Villa Park, Illinois  60181-2206
Lines: 29

jpr@jpradley.jpr.com (Jean-Pierre Radley) wrote in
<1991May22.191522.19709@jpradley.jpr.com>:

| >From the keyboard of felps@convex.com (Robert Felps):
| >:I don't know of any way to sort based on right to left. But you might try


| With awk, $NF is the last field. So pipe the file through awk, prepending
| the last field ($NF) to the whole line ($0), separated by something wierd,
| say ^B. Pipe this to sort, then pipe to a sed to ditch characters up to and
| including the ^B.
| As I think of it, the first awk could be a sed filter too.

You know, if you're looking to replace the original file with a sorted one,
you could do the whole thing in ex.  Let's say your field separator is a
space:

ex - file << \,,
%s/.* \(.*\)/\1 &/
%!sort
%s/[^ ]* //
wq
,,

David Tamkin  PO Box 7002  Des Plaines IL  60018-7002  dattier@vpnet.chi.il.us
GEnie:D.W.TAMKIN  CIS:73720,1570  MCIMail:426-1818  708 518 6769  312 693 0591

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