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From: martin@mwtech.UUCP (Martin Weitzel)
Newsgroups: comp.unix.questions
Subject: Re: $argv[$#argv]
Message-ID: <1154@mwtech.UUCP>
Date: 27 May 91 23:04:57 GMT
References: <1991May25.204543.6428@midway.uchicago.edu> <16278@smoke.brl.mil>
Reply-To: martin@mwtech.UUCP (Martin Weitzel)
Organization: MIKROS Systemware, Darmstadt/W-Germany
Lines: 23

In article <16278@smoke.brl.mil> gwyn@smoke.brl.mil (Doug Gwyn) writes:
>In article <1991May25.204543.6428@midway.uchicago.edu> goer@ellis.uchicago.edu (Richard L. Goerwitz) writes:
>>It's not obvious to me how to take the value of the last argv
>>element with /bin/sh, the way one can do with the C-Shell using
>>subscripts.  Perhaps an ignorant question, but how do?

Yes, you're right, it's ignorant - especially ignorant of the FAQ posted
monthly to this group (refer to question #32).

>It's somewhat context sensitive, but here's one example:
>	$ set -- a b c
>	$ echo `eval echo $"$#"`
>	c

But as Doug was already kind enough to post one possible solution, I'll
post another (which happens to be my favorite as it works on ALL flavours
of the bourne shell and with ANY number of arguments):

	for last do :; done

Now the last argument is left in the shell variable last.
-- 
Martin Weitzel, email: martin@mwtech.UUCP, voice: 49-(0)6151-6 56 83