Path: utzoo!utgpu!news-server.csri.toronto.edu!bonnie.concordia.ca!uunet!mcsun!ukc!slxsys!stevem From: stevem@specialix.co.uk (Steven Murray) Newsgroups: sci.electronics Subject: Re: Drawing DC phone current Keywords: SK2086, phones Message-ID: <1991May29.084859.5324@specialix.co.uk> Date: 29 May 91 08:48:59 GMT References: <1081@eplunix.UUCP> <8053@nst> <1084@eplunix.UUCP> Organization: Specialix International, London Lines: 39 raoul@eplunix.UUCP (Nico Garcia) writes: >In article <8053@nst>, grayt@Software.Mitel.COM (Tom Gray) writes: >> Draw less than 4mA from the loop and you will not have any >> problems. >Only works in the off-hook position, Tom. A standard phone is about 600 >ohms, and has about 10 Volts across it off-hook. That's *about* 15-20 mA: >the standards are deliberately extremely broad. It's not clear at all to me >that 4 mA will not maintain the "off-hook" status in the phone company's >circuits. However, the phone company does *not* want DC paths available for >the on-hook state. I'm sure it is true the phone company does not want the DC path - nevertheless they do allow for some leakage across the circuit. The original poster was about right I think. >In fact, let me go try this (putting a 2700 ohm resistor across my office >phone line). Hmmm: goes off-hook as the voltage drops to 18 volts. Maybe my >line is picky, but forcing it off-hook is not what *I* want from an >in-use detector. You used 2700 ohms - but the off-hook voltage was something like 18 volts - thats not 4 milliamps. Just leave the 4 milliamps bit for a moment, try a resistor of value 22k. Its still not 'proper' but I think you will find it works. I'm not suggesting you do this on anything but your own private telephone exchange :-) >-- > Nico Garcia > Designs by Geniuses for use by Idiots > eplunix!cirl!raoul@eddie.mit.edu -- Steven Murray uunet!slxsys!stevem stevem@specialix.co.uk I am speaking, but | If these are your opinions, then we are in agreement!! not for my employer.| Flames, spelling errors, complaints > /dev/null