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From: wreck@fmsrl7.UUCP (Ron Carter)
Newsgroups: sci.electronics,sci.energy
Subject: Re: Gold saves energy.
Summary: Pull out your calculator, it's time to have fun.
Keywords: gold
Message-ID: <43275@fmsrl7.UUCP>
Date: 5 Jun 91 13:20:18 GMT
References: <sehari.676081817@du248-12.cc.iastate.edu>
Reply-To: wreck@fmsrl7.UUCP (Ron Carter)
Organization: Ford Motor Company, Scientific Research Labs, Dearborn, MI
Lines: 24

In article <sehari.676081817@du248-12.cc.iastate.edu> sehari@iastate.edu (Sehari Babak) writes:
>... I am curious that haw much energy would we save. If
>we gold plate all Al wires that is used for transportation of the energy?
>
>Has any research been conducted in this way of saving energy.    

Conduct your own research.  It's easy!

1.)	Compute the amount of gold a dollar will buy.  (It's
	about $350 for 1 Troy ounce, or 1/14 lb).
2.)	Compute the amount of aluminum a dollar will buy.
	(Scrap is selling for around $1/lb; new might be $2.)
3.)	Compute the diameter of a meter-long gold wire
	containing your $1 of gold.
4.)	Compute the diameter of a meter-long aluminum wire
	containing your $1 of aluminum.
5.)	Using values for impedance of metals (available in
	the CRC Handbook of Chemistry and Physics), compute
	the resistance of the two meter-long wires.

The wire with the lower resistance would deliver power with
smaller losses for the same cost, and is the energy-saving winner.

So.  What answer did you come up with?