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From: epperly@cs.odu.edu (William "Badger" Epperly)
Newsgroups: comp.binaries.ibm.pc.d
Subject: INT 19h
Summary: trying to disable ctl-alt-del
Keywords: INT 19h
Message-ID: <1991Jun26.161654.5835@cs.odu.edu>
Date: 26 Jun 91 16:16:54 GMT
References: <1991Jun22.023415.12914@odin.corp.sgi.com>
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Problem:  I am writing a small program which I do not want the user
          to be able to kill with a warm boot command.  I am writing
	  on a 386sx machine using Turbo C++'s ansi C compiler.  I have
	  used the routine 
		getvect(0x19) 
	  to get the address of the original routine which I save in
	  a properlly declared variable.  I then use
		setvect(0x19,<routine name>)
	  to set the new routines address in the interrupt vector table.
	  I have then issued another call to getvect(0x19) to see if
	  the value in the interrupt vector table has been changed.
  	  It was changed.
	  The problem is that when ctl-alt-del is entered by the
	  user, the machine performs a warm boot anyway.  My Question
	  is, what am I not doing or doing wrong.  BTW, I have turned
	  of the "check stack overflow" box for the compiler and my
	  code is executable.  
	
	  Please mail your responses to 
		epperly@cs.odu.edu
	  and I will post a summary.
	  Thanks in advance for your help.