Apyuxjj.176
net.math
utzoo!decvax!harpo!eagle!mhuxt!pyuxjj!rlr
Wed May  5 12:11:50 1982
Re: Solution(?) to oldie but goodie
	sqrt(-1) = i      sqrt(1) = 1
	sqrt(1/-1) = sqrt(-1) = i
	sqrt(1)/sqrt(-1) = 1/i
	1/i = i  (????????)

	OR  i**2 = 1 (??????)

I guess sqrt(a/b) != sqrt(a)/sqrt(b) where imaginaries are concerned.
(Did I do that right?)  Could someone explain.
		Rich Rosen pyuxjj!rlr