Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10 5/26/83; site ihuxr.UUCP Path: utzoo!linus!decvax!harpo!eagle!mhuxt!mhuxi!cbosgd!ihnp4!ihuxr!lew From: lew@ihuxr.UUCP Newsgroups: net.math Subject: Identity reference found Message-ID: <550@ihuxr.UUCP> Date: Thu, 11-Aug-83 18:31:04 EDT Article-I.D.: ihuxr.550 Posted: Thu Aug 11 18:31:04 1983 Date-Received: Sat, 13-Aug-83 02:56:11 EDT Organization: BTL Naperville, Il. Lines: 20 John Riordan gives my "interesting identity" as an example on page 4 of his appropriately titled book, "Combinatorial Identities". He gives the inductive proof but he skips most of the algebra. He takes things one step further. Having defined the inverse relations: a(n) = sum k=0,n of (-1)^k * C(n,k) * b(k) b(n) = sum k=0,n of (-1)^k * C(n,k) * a(k) ... he lets b(0)=0, b(k) = 1/k. This gives for a(n) the negative of the expression we just showed equal to 1 + 1/2 + ... + 1/n. The second relation then relates 1/n to a sum over sums of 1/k. He shows this directly then states, "The first derivation is somewhat simpler, thus providing a point to the Jacobian injunction 'always invert'." A point? ... oh well, he's only up to page 5! Lew Mammel, Jr. ihuxr!lew