Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10 5/3/83; site hou5d.UUCP Path: utzoo!linus!decvax!harpo!eagle!mhuxt!mhuxi!mhuxa!houxm!hogpc!houca!orion!hou5f!hou5e!hou5d!kwmc From: kwmc@hou5d.UUCP Newsgroups: net.math Subject: Re: Everything you know is wrong ! Message-ID: <604@hou5d.UUCP> Date: Tue, 16-Aug-83 10:48:23 EDT Article-I.D.: hou5d.604 Posted: Tue Aug 16 10:48:23 1983 Date-Received: Wed, 17-Aug-83 05:46:31 EDT Organization: American Bell ED&D, Holmdel, NJ Lines: 27 The following 'proof' appeared in net.math recently .... ---------------------------------------------------------------------- It is often said that a sphere has the smallest ratio of surface area to volume among possible shapes. (See net.sf-lovers) ... Well, here's proof to the contrary! For the sphere: ratio = ( 4*pi*r^2 ) / ( 4/3*pi*r^3 ) = 3/r For the cylinder circumscribed on the sphere: ratio = (height * circumference + 2 * base) / ( height * base ) = ( 2*r * 2*pi*r + 2 * pi*r^2 ) / (2*r * pi*r^2) = 3/r The same as for the sphere!!! Lew Mammel, Jr. ihuxr!lew ---------------------------------------------------------------------- well it seems very tempting to believe it at first UNTIL you realise that the ratio is dependant on 'r'. The shape of the cylinder could be molded into a sphere ( of the same volume ) but in which the value of 'r' is greater, and thus the ratio 3/r IS smaller as it should be. Remember, for the same volume the 'r's are different, also 3/r is NOT a constant it varies with the value of 'r'. Ken Cochran hou5d!kwmc