Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10 5/3/83; site houxz.UUCP Path: utzoo!linus!decvax!harpo!gummo!whuxlb!pyuxll!eisx!npoiv!npois!hogpc!houxm!houxz!halle1 From: halle1@houxz.UUCP Newsgroups: net.math,net.misc,net.rec.bridge Subject: Re: simple (?) statistics problem solved Message-ID: <414@houxz.UUCP> Date: Fri, 19-Aug-83 14:04:15 EDT Article-I.D.: houxz.414 Posted: Fri Aug 19 14:04:15 1983 Date-Received: Fri, 19-Aug-83 21:34:16 EDT References: <1287@tektronix.UUCP> Organization: Bell Labs, Holmdel NJ Lines: 8 You are making a major mistake. You were told that ONE was gold, not that the first was gold. In essence, the question asks: given four coins, one of which is silver, the rest gold, you pick a gold one. What is the chance that your next selection is also gold? Obviously the answer is 2/3. Remember, everything was done at random. Reread the solution carefully, and with an open mind. You should see that it is correct. (I bet every bridge player worth his master points got this one right.)