Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP
Path: utzoo!linus!decvax!harpo!gummo!whuxlb!pyuxll!eisx!npoiv!npois!hogpc!houxm!ihnp4!ixn5c!inuxc!pur-ee!ecn-ec:ecn-pc:ecn-ed:vu
From: ecn-ec:ecn-pc:ecn-ed:vu@pur-ee.UUCP
Newsgroups: net.math,net.misc,net.rec.bridge
Subject: Re: simple (?) statistics problem solved
Message-ID: <163@ecn-ed.UUCP>
Date: Tue, 23-Aug-83 21:21:18 EDT
Article-I.D.: ecn-ed.163
Posted: Tue Aug 23 21:21:18 1983
Date-Received: Wed, 24-Aug-83 13:06:56 EDT
References: <1814@rabbit.UUCP> utcsstat.903
Lines: 20


	I agree with Laura Creighton in the point that the all silver cabinet
is irrelevant to the problem: 'toss it out the window', or put in there a dozen
other won't make any difference. But the result IS 2/3. The answer I mailed to
rabbit!ark was this:
	Let's call the all gold cabinet cabinet 1.
                   the gold-silver cabinet cabinet 2(gold in drawer 1, silver
                                                     in drawer 2 )
Then, on the first pick, it may have been:
1) drawer 1 cabinet 1
2)	drawer 2 cabinet 1
3)	drawer 1 cabinet 2.

Of these possibilities, 2 of them gives you a second gold coin: cases 1 & 2.
Thus, the probability is 2/3.

Hao-Nhien Vu (pur-ee!vu )
PS: If you want to mail anything to me, please send to pur-ee!norris because
pur-ee!vu  will be terminated early this semester, that is within a week from
today.