Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10 5/3/83; site hou5d.UUCP Path: utzoo!linus!philabs!cmcl2!floyd!vax135!ariel!hou5f!hou5g!hou5h!hou5a!hou5d!kwmc From: kwmc@hou5d.UUCP (K. W. M. Cochran) Newsgroups: net.math Subject: Re: A statistics paradox Message-ID: <663@hou5d.UUCP> Date: Mon, 19-Sep-83 09:23:20 EDT Article-I.D.: hou5d.663 Posted: Mon Sep 19 09:23:20 1983 Date-Received: Tue, 20-Sep-83 20:02:42 EDT References: <205@ecn-ed.UUCP> Organization: American Bell ED&D, Holmdel, NJ Lines: 17 Let p = .5 be the probability that a phenomenum will happen to an item. Thus the probability that it won't happen is 1-p = .5 So with a population of 2, the probability that the phenomenum happens to at least one of the items will be p+p = 1 , while the probability that the phenomenum will not happen to either is (1-p)(1-p) = .25 hence making a total of 1.25 ?!?! Where did I go wrong ? Hao-Nhien Vu (pur-ee!norris) ************************************************************************** Your slip up was when you assumed that the probability that the phenomenum happens to at least one item is p+p. This probability is 1-(p*p) = .75 Ken Cochran hou5d!kwmc