Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10 5/26/83; site ihuxr.UUCP Path: utzoo!linus!philabs!cmcl2!floyd!clyde!ihnp4!ihuxr!lew From: lew@ihuxr.UUCP (Lew Mammel, Jr.) Newsgroups: net.math Subject: Re: missing card problem Message-ID: <668@ihuxr.UUCP> Date: Wed, 28-Sep-83 18:29:33 EDT Article-I.D.: ihuxr.668 Posted: Wed Sep 28 18:29:33 1983 Date-Received: Fri, 30-Sep-83 03:39:20 EDT Organization: BTL Naperville, Il. Lines: 15 R. Wienski wonders why 7/46 disagrees with the Bayesian answer. He erred by not including the missing card among the cards remaining after the 5 clubs are drawn. The answer is 8/47. Note that : 13*12*11*10*9 13 12*11*10*9*8 ------------- = -- * ------------ 51*50*49*48*47 8 51*50*49*48*47 Calling this value "A", the Bayesian answer becomes: 8/13 * A / ( 8/13 * A + 3*A ) = 8/47 It doesn't matter if the 5 clubs are drawn before or after the card is lost. Lew Mammel, Jr. ihuxr!lew