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From: ka@hou3c.UUCP (Kenneth Almquist)
Newsgroups: net.math
Subject: Re: binary expansion of 1/n
Message-ID: <129@hou3c.UUCP>
Date: Tue, 29-Nov-83 17:29:32 EST
Article-I.D.: hou3c.129
Posted: Tue Nov 29 17:29:32 1983
Date-Received: Thu, 1-Dec-83 03:20:24 EST
References: <685@sunybcs.UUCP> <1328@burdvax.UUCP>
Organization: Bell Labs, Holmdel, NJ
Lines: 13

The question does not specificly say that leading and trailing zeros are
to be counted.  If they are not counted, then the answer is n = 1.  If
leading and trailing zeros *are* to be included, then the number of zero
digits will be infinite for any n.  This means that the number of zero
digits will be equal to the total number of digits.  Since the number of
one's digits cannot be greater than the total number of digits, the number
of one's digits cannot be greater than the number of zero digits for any
n.

The preceding paragraph may be a little dense, but the important point
is that the concept of greater than is somewhat nonintuitive when infinite
quantities are involved.
					Kenneth Almquist