Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Path: utzoo!watmath!clyde!akgua!mcnc!ncsu!uvacs!gmf From: gmf@uvacs.UUCP Newsgroups: net.math Subject: Interesting Numbers Message-ID: <1279@uvacs.UUCP> Date: Sat, 5-May-84 10:25:42 EDT Article-I.D.: uvacs.1279 Posted: Sat May 5 10:25:42 1984 Date-Received: Sun, 6-May-84 07:38:18 EDT Lines: 25 >> But the "proof" that there is no "uninteresting" number by >> emiminating the smallest such one at a time is invalid I'm not sure my "proof" is being referred to, but maybe I ought to expand it: Let U be the set of uninteresting numbers, and suppose (by way of contradiction) that U is non-empty. Then U has a least element x (by a principle equivalent to the axiom of mathematical induction). Then x is uninteresting by virtue of being in U. But surely x is interesting by virtue of being the least uninteresting positive integer (like 1729 is interesting by virtue of being the least positive integer which is the sum of 2 cubes in 2 different ways). Thus x is both uninteresting and interesting, a contradiction. This arose from assuming U non-empty. Thus U, the set of uninteresting positive integers, is empty. Thus all positive integers are interesting. To call this proof "invalid" is to call the axiom of mathematical induction invalid. A proof by mathematical induction does not proceed by considering one case at a time until all cases are taken care of. This is only possible for finite sets. Gordon Fisher