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From: wickart@iuvax.UUCP
Newsgroups: net.sport.baseball
Subject: solution to 4 outs problem
Message-ID: <9400003@iuvax.UUCP>
Date: Wed, 9-May-84 16:49:00 EDT
Article-I.D.: iuvax.9400003
Posted: Wed May  9 16:49:00 1984
Date-Received: Sat, 12-May-84 07:43:02 EDT
Lines: 16
Nf-ID: #N:iuvax:9400003:000:980
Nf-From: iuvax!wickart    May  9 15:49:00 1984


Due to many requests, here is the solution to the problem of getting
four LEGAL OUTS (not just strkeouts for the pitcher) in one inning:
   Assume one out, Andrews on third, Beeblebrox on first, Carmen at
the plate. Carmen hits a long fly, which is caught (Second out). Andrews
breaks for the plate. The throw from the outfield gets there too late.
As Beeblebrox rounds second, he is caught in a rundown, and eventually
tagged out (Third out). Since there was a break in continuity of the
play, the run is, at present time, good. The third basean calls for
the ball, steps on third, and appeals to the umpire that Andrews left
before the fly was caught. The appeal is upheld, and the scorer is
required to score a fourth out in order to nullify the run, with a
fourth put-out credited to the third baseman.
   Note that, with the bases loaded and two outs, an apparent inside-
the park home run could, with four appeals, produce SIX outs in an
inning under the same scoring rule.