Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Path: utzoo!watmath!clyde!burl!ulysses!unc!mcnc!ecsvax!pizer From: pizer@ecsvax.UUCP Newsgroups: net.math,net.puzzle Subject: Geometry Puzzle III Message-ID: <2915@ecsvax.UUCP> Date: Wed, 11-Jul-84 18:42:44 EDT Article-I.D.: ecsvax.2915 Posted: Wed Jul 11 18:42:44 1984 Date-Received: Thu, 12-Jul-84 05:28:18 EDT Lines: 12 Just to keep you on your toes, I have ANOTHER problem, this one I have yet to solve, although I've just about got it (decided to put it up before din-din). This figure is more difficult to draw, so read through the description before trying to draw it. First start with right triangle ABC, where A is rt. and where AC is the longer leg. Then draw point D on side AC, such that DB=DC. Finally, draw point F on BC such that AF is perpindicular, and such that CF=CD. Given: BD=DC=FC=1 and that AB is prpndclr to AC and that AF is prpndclr to BC, FIND: AC. Good luck, leave answer in radical form. Billy Pizer (pizer@ecsvax) {look out M.C.!}