Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10.1 6/24/83 SMI; site ur-laser.uucp Path: utzoo!watmath!clyde!burl!ulysses!unc!mcnc!decvax!tektronix!hplabs!hao!seismo!rochester!ur-laser!james From: james@ur-laser.uucp (James Chavin) Newsgroups: net.math Subject: an eggsacting problem(a solution) Message-ID: <247@ur-laser.uucp> Date: Mon, 27-Aug-84 14:22:46 EDT Article-I.D.: ur-laser.247 Posted: Mon Aug 27 14:22:46 1984 Date-Received: Wed, 29-Aug-84 00:59:58 EDT Organization: Lab for Laser Energetics, Univ. of Rochester Lines: 33 I am posting the solution to the hens amd the eggs. The posted solution is one I received from Chris Stassen. I know that a lot of people claim that a half a hen can't lay half an egg, but you must remember that it is only a rate If you don't believe me, try chopping a hen in half and see how long it takes to lay half an egg. Thanks to all the people who sent me answers. James Chavin > If a hen-and-a-half can lay an egg-and-a-half in an hour-and-a-half, > how long does it take two hens to lay three eggs? Assuming that any hen can always lay the same number of eggs in a given time period, then: (1) [Assumption] (eggs)/(hens)(time) is constant. (2) [Given] 1.5 eggs, 1.5 hens, and 1.5 hours. (3) [(1) & (2)] For any hens (H), eggs (E) and time (T), E/HT is always the same number. Since we have one E, H, and T, we know that every E/HT = (1.5)/(1.5)(1.5) = 2/3. (4) [Given] 2 hens, 3 eggs, unknown time. (5) [(3) & (4)] E/HT = 2/3 --> (3)/(2)T = 2/3 --> T = 9/4 = 2.25 hours. --------------------------------------------------------------------