Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: $Revision: 1.6.2.14 $; site uiucdcs.UUCP Path: utzoo!watmath!clyde!burl!ulysses!mhuxl!ihnp4!inuxc!pur-ee!uiucdcs!mcewan From: mcewan@uiucdcs.UUCP Newsgroups: net.women Subject: Re: Re: rape statistics - (nf) Message-ID: <31600087@uiucdcs.UUCP> Date: Tue, 11-Sep-84 15:06:00 EDT Article-I.D.: uiucdcs.31600087 Posted: Tue Sep 11 15:06:00 1984 Date-Received: Fri, 14-Sep-84 06:53:19 EDT References: <4040@tekecs.UUCP> Lines: 37 Nf-ID: #R:tekecs:-404000:uiucdcs:31600087:000:1608 Nf-From: uiucdcs!mcewan Sep 11 14:06:00 1984 #R:tekecs:-404000:uiucdcs:31600087:000:1608 uiucdcs!mcewan Sep 11 14:06:00 1984 I think everyone is missing something. If I remember correctly, the 500,000 figure was the total female population of the city. If there's only a small range of ages in which women are raped (which I'm not convinced is the case) then you have to reduce that 500,000 figure to the number of women in that age range. However, if you don't make any assumptions at all about age, use the total number of females, and use the average life span as the window, you get the same result! The original posting that suggested a 50 year window was too conservative. Having said that, I now make a 180 degree turn and say that I think that the above calculation is too simplistic. For one thing, it assumes that each victim will only be raped once (I'm not sure if the 700 figure was number of rapes or victims, so we may have a source of error right there.) If, for example, we assume that the probability of getting raped is the same regardless of age or previous attacks, the percentage would be 1 - (1- ((700/500000) * fudge factor)) ^ expected life span which is considerable different. A more accurate figure could be obtained by getting a breakdown of ages for the rape statistics and population, and calculating 1 - product i=1..whatever {1 - ((# women age i reporting rapes) / (# women of age i)) * fudge factor(i)} A lot would depend on the fudge factors, which would probably have a lot of errors (there is a certain amount of guesswork involved) which makes this calculation highly suspect. Scott McEwan pur-ee!uiucdcs!mcewan "Just because something is obvious doesn't mean that it's true."