Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10.2 9/5/84; site gloria.UUCP Path: utzoo!linus!philabs!cmcl2!seismo!rochester!rocksanne!sunybcs!gloria!colonel From: colonel@gloria.UUCP (George Sicherman) Newsgroups: net.physics Subject: Re: black pots Message-ID: <690@gloria.UUCP> Date: Tue, 20-Nov-84 11:13:22 EST Article-I.D.: gloria.690 Posted: Tue Nov 20 11:13:22 1984 Date-Received: Sun, 25-Nov-84 08:46:05 EST References: <2559@dartvax.UUCP> <642@watdcsu.UUCP> <380@x.UUCP> Organization: SUNY-Buffalo Confuser Science Lines: 57 ["... and you know what happens with a Black Pot." --John Lennon] This appeared in net.cooks. Any comment from you in net.physics? > > I still can't believe the ignorance prevailing in journalism today! > > For someone to draw the conclusion that since black cars get hot in > > the sun, then black pots must radiate lots of waste heat is > > incredulous! This person should have at least consulted a basic > > physics text. > > WRONGO, CONS BREATH! > > My basic physics text: > "Quantum Physics of Atoms, Molecules, Solids, Nuclei, and Particles" by > Robert Eisberg and Robert Resnick, (c) 1974 John Wiley and Sons, New York. > @begin(quote) > Example 1-2, page 7 (boy, this has to be basic): > > Assume we have two small opaque bodies a large distance from one another > supported by fine threads in a large evacuated enclosure whose walls are > opaque and kept at a constant temperature. IN SUCH A CASE THE BODIES AND > WALLS CAN EXCHANGE ENERGY ONLY BY MEANS OF RADIATION. Let (e) represent > the rate of emission of radiant energy by a body and let (a) represent > the rate of absorption of radiant energy by a body. Show that at equilibrium > > e1 e2 > ---- = ---- = 1 (1-5) > a1 a2 > > This relation, (1-5), is known as "Kirchoff's law for radiation." > Proof: > The equilibrium state is one of constant temperature throughout the enclosed > system, and in that state the emission rate necessarily equals the absorption > rate for each body. Hence > > e1 = a1 and e2 = a2 > Therefore: > e1 e2 > ---- = 1 = ---- > a1 a2 > > If one body, say body 2, is a blackbody, then a2 > a1 because a blackbody is > a better absorber than a non-blackbody. HENCE, IT FOLLOWS FROM (1-5) THAT > e2 > e1. THE OBSERVED FACT THAT GOOD ABSORBERS ARE ALSO GOOD EMITTERS IS THUS > PREDICTED BY KIRCHOFF'S LAW. > @end(quote) > > Emphasis mine. > > Good absorbers of radiant energy are good emitters of radiant energy. > > John Woods > B.S. Physics, MIT 1982 > B.S. Electrical Engineering/Computer Science, MIT 1982 -- Col. G. L. Sicherman ...seismo!rochester!rocksanne!rocksvax!sunybcs!gloria!colonel