Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10.1 6/24/83; site inuxc.UUCP Path: utzoo!watmath!clyde!cbosgd!ihnp4!inuxc!fred From: fred@inuxc.UUCP (Fred Mendenhall) Newsgroups: net.space,net.columbia Subject: orbit-60 cents/pound Message-ID: <1078@inuxc.UUCP> Date: Fri, 16-Nov-84 10:32:25 EST Article-I.D.: inuxc.1078 Posted: Fri Nov 16 10:32:25 1984 Date-Received: Mon, 19-Nov-84 03:16:23 EST Organization: AT&T Consumer Products Div., Indianapolis Lines: 37 I would like to thank those of you who responded to my mass driver question. The reply that I found the most interesting was from Keith Lofstrom. His analysis clearly ignores atmospheric friction and conversion losses, yet I'm sure that is how the 60 cents per pound number was originally calculated. (AT that price even I could afford to get away from it all) Fred +++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++ In reply to your news message --- Cost to escape: One pound = 0.454 Kg Escape Velocity = 11,000 m/s Energy per pound = 1/2 * m * v^2 = 0.5 * 0.454 * 11000^2 Joules = 27.4 M Joules 1 Kilowatt-Hour = 1000 Watts * 3600 Seconds = 3.6 M Joules Energy per pound = 27.4 M / 3.6 M KWHr = 7.63 KWHr At 4 cents per KWHr (Pacific Northwest) that's 30.5 cents per pound to escape. At 8 cents per KWHr (NYC?) that's 61 cents. The how, of course, is just an engineering detail... Keith Lofstrom uucp: {ucbvax,decvax,chico,pur-ee,cbosg,ihnss}!tektronix!vice!keithl CSnet: keithl@tek ARPAnet:keithl.tek@rand-relay